What are the solutions to the equation 2x^2+3x+7=0 ?

The solutions to the equation 2x^2+3x+7=0 are x=-3/4+i(sqrt(47))/4 ,x=-3/4-i(sqrt(47))/4

Find the zeros of 2x^2+3x+7=0

The zeros of 2x^2+3x+7=0 are x=-3/4+i(sqrt(47))/4 ,x=-3/4-i(sqrt(47))/4

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2 x^{2} + 3 x + 7 = 0

x = - \frac{3}{4} + i \frac{47}{4}, x = - \frac{3}{4} - i \frac{47}{4}

Solution steps

2 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 7 : 47 i

x_{1, 2} = \frac{- 3 \pm 47 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 47 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 47 i}{2 \cdot 2}

x = \frac{- 3 + 47 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{47}{4}

x = \frac{- 3 - 47 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{47}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{47}{4}, x = - \frac{3}{4} - i \frac{47}{4}

x^{2} - 7 x + 16 = 0

10 x - 8 + 3 x - 7 + x = 20 x - 10 - 6 x

x^{(2)} - 4 x = 21

\frac{8}{- 12 i}

4 (x + 1) - 7 = 3 (x - 1) + x

What are the solutions to the equation 2x^2+3x+7=0 ?
The solutions to the equation 2x^2+3x+7=0 are x=-3/4+i(sqrt(47))/4 ,x=-3/4-i(sqrt(47))/4
Find the zeros of 2x^2+3x+7=0
The zeros of 2x^2+3x+7=0 are x=-3/4+i(sqrt(47))/4 ,x=-3/4-i(sqrt(47))/4