What are the solutions to the equation 0.6x^2-1.2x-0.6=0 ?

The solutions to the equation 0.6x^2-1.2x-0.6=0 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of 0.6x^2-1.2x-0.6=0

The zeros of 0.6x^2-1.2x-0.6=0 are x=1+sqrt(2),x=1-sqrt(2)

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0.6 x^{2} - 1.2 x - 0.6 = 0

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

0.6 x^{2} - 1.2 x - 0.6 = 0

Multiply both sides by

10

6 x^{2} - 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 6) = 122

x_{1, 2} = \frac{- ( - 12 ) \pm 12 2}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 2}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 12 2}{2 \cdot 6}

x = \frac{- ( - 12 ) + 12 2}{2 \cdot 6} : 1 + 2

x = \frac{- ( - 12 ) - 12 2}{2 \cdot 6} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

64 t^{3} - 1

x^{2} + 2 x + 10 = 0

∣ x - 8 ∣ \geq - 6

x^{4} - 5 x^{2} + 4 \leq 0

∣ 3 x - 5 ∣ > x^{2} - 3 x

What are the solutions to the equation 0.6x^2-1.2x-0.6=0 ?
The solutions to the equation 0.6x^2-1.2x-0.6=0 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of 0.6x^2-1.2x-0.6=0
The zeros of 0.6x^2-1.2x-0.6=0 are x=1+sqrt(2),x=1-sqrt(2)