What are the solutions to the equation -3x^2+5x+3=0 ?

The solutions to the equation -3x^2+5x+3=0 are x=-(-5+sqrt(61))/6 ,x=(5+sqrt(61))/6

Find the zeros of -3x^2+5x+3=0

The zeros of -3x^2+5x+3=0 are x=-(-5+sqrt(61))/6 ,x=(5+sqrt(61))/6

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- 3 x^{2} + 5 x + 3 = 0

x = - \frac{- 5 + 61}{6}, x = \frac{5 + 61}{6}

Decimal Notation

x = - 0.46837 \dots, x = 2.13504 \dots

Solution steps

- 3 x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) \cdot 3}{2 ( - 3 )}

5^{2} - 4 (- 3) \cdot 3 = 61

x_{1, 2} = \frac{- 5 \pm 61}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 61}{2 ( - 3 )}, x_{2} = \frac{- 5 - 61}{2 ( - 3 )}

x = \frac{- 5 + 61}{2 ( - 3 )} : - \frac{- 5 + 61}{6}

x = \frac{- 5 - 61}{2 ( - 3 )} : \frac{5 + 61}{6}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 61}{6}, x = \frac{5 + 61}{6}

2 y^{2} - 11 y + 5

x^{2} + 5 x - 14 \geq 0

x (x - 4) \leq 5

x^{2} + 6 x = 91

2 - 6

What are the solutions to the equation -3x^2+5x+3=0 ?
The solutions to the equation -3x^2+5x+3=0 are x=-(-5+sqrt(61))/6 ,x=(5+sqrt(61))/6
Find the zeros of -3x^2+5x+3=0
The zeros of -3x^2+5x+3=0 are x=-(-5+sqrt(61))/6 ,x=(5+sqrt(61))/6