What are the solutions to the equation x^2+6x=91 ?

The solutions to the equation x^2+6x=91 are x=7,x=-13

Find the zeros of x^2+6x=91

The zeros of x^2+6x=91 are x=7,x=-13

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x^{2} + 6 x = 91

x = 7, x = - 13

Solution steps

x^{2} + 6 x = 91

Move

91

to the left side

x^{2} + 6 x - 91 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 91 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 91) = 20

x_{1, 2} = \frac{- 6 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 20}{2 \cdot 1}, x_{2} = \frac{- 6 - 20}{2 \cdot 1}

x = \frac{- 6 + 20}{2 \cdot 1} : 7

x = \frac{- 6 - 20}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 7, x = - 13

2 - 6

x^{2} - 3 x - 4 = - 4 x - 2

- 4 x^{2}

\frac{\frac{x ^{3} + y ^{3}}{x + y}}{( x ^{2} - x y + y ^{2} )}

- \frac{10}{4}

What are the solutions to the equation x^2+6x=91 ?
The solutions to the equation x^2+6x=91 are x=7,x=-13
Find the zeros of x^2+6x=91
The zeros of x^2+6x=91 are x=7,x=-13