What are the solutions to the equation x^2-3x-4=-4x-2 ?

The solutions to the equation x^2-3x-4=-4x-2 are x=1,x=-2

Find the zeros of x^2-3x-4=-4x-2

The zeros of x^2-3x-4=-4x-2 are x=1,x=-2

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x^{2} - 3 x - 4 = - 4 x - 2

x = 1, x = - 2

Solution steps

x^{2} - 3 x - 4 = - 4 x - 2

Move

2

to the left side

x^{2} - 3 x - 2 = - 4 x

Move

4 x

to the left side

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

- 4 x^{2}

\frac{\frac{x ^{3} + y ^{3}}{x + y}}{( x ^{2} - x y + y ^{2} )}

- \frac{10}{4}

w^{2} - 9 w + 20 = 0

7 x + 2 \leq 16

What are the solutions to the equation x^2-3x-4=-4x-2 ?
The solutions to the equation x^2-3x-4=-4x-2 are x=1,x=-2
Find the zeros of x^2-3x-4=-4x-2
The zeros of x^2-3x-4=-4x-2 are x=1,x=-2