What are the solutions to the equation x^2+10x-25=0 ?

The solutions to the equation x^2+10x-25=0 are x=5(sqrt(2)-1),x=-5(1+sqrt(2))

Find the zeros of x^2+10x-25=0

The zeros of x^2+10x-25=0 are x=5(sqrt(2)-1),x=-5(1+sqrt(2))

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x^{2} + 10 x - 25 = 0

x = 5 (2 - 1), x = - 5 (1 + 2)

Solution steps

x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 25) = 102

x_{1, 2} = \frac{- 10 \pm 10 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 10 2}{2 \cdot 1}

x = \frac{- 10 + 10 2}{2 \cdot 1} : 5 (2 - 1)

x = \frac{- 10 - 10 2}{2 \cdot 1} : - 5 (1 + 2)

The solutions to the quadratic equation are:

x = 5 (2 - 1), x = - 5 (1 + 2)

(3 x - 1)^{2} - 5 (x - 2) - (2 x + 3)^{2} - (5 x + 2) (x - 1) = 0

9 r^{2} - 3 = - 152

- \frac{\frac{4}{5}}{\frac{3}{5}}

7 x - 4 = 3 + 8 x

3 (6)^{2}

What are the solutions to the equation x^2+10x-25=0 ?
The solutions to the equation x^2+10x-25=0 are x=5(sqrt(2)-1),x=-5(1+sqrt(2))
Find the zeros of x^2+10x-25=0
The zeros of x^2+10x-25=0 are x=5(sqrt(2)-1),x=-5(1+sqrt(2))