What are the solutions to the equation 2x^2+13x+15=0 ?

The solutions to the equation 2x^2+13x+15=0 are x=-3/2 ,x=-5

Find the zeros of 2x^2+13x+15=0

The zeros of 2x^2+13x+15=0 are x=-3/2 ,x=-5

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2 x^{2} + 13 x + 15 = 0

x = - \frac{3}{2}, x = - 5

Solution steps

2 x^{2} + 13 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 15 = 7

x_{1, 2} = \frac{- 13 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 7}{2 \cdot 2}, x_{2} = \frac{- 13 - 7}{2 \cdot 2}

x = \frac{- 13 + 7}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 13 - 7}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 5

(2 x + 1)^{2} = (x - 1)^{2} + 3 x (x + 2)

4^{3} \cdot x^{2} \cdot (\frac{4}{x})^{- 2}

- 5 x - 9 \leq - \frac{3 x}{2}

3 (v + 2) - v = 2 (v - 1) + 5

y^{2} - 8 y = - 14

What are the solutions to the equation 2x^2+13x+15=0 ?
The solutions to the equation 2x^2+13x+15=0 are x=-3/2 ,x=-5
Find the zeros of 2x^2+13x+15=0
The zeros of 2x^2+13x+15=0 are x=-3/2 ,x=-5