What is the answer to (2x+1)^2=(x-1)^2+3x(x+2) ?

The answer to (2x+1)^2=(x-1)^2+3x(x+2) is True for all x

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(2x+1)^2=(x-1)^2+3x(x+2)

(2 x + 1)^{2} = (x - 1)^{2} + 3 x (x + 2)

True for all x

Solution steps

(2 x + 1)^{2} = (x - 1)^{2} + 3 x (x + 2)

Expand

(2 x + 1)^{2} : 4 x^{2} + 4 x + 1

Expand

(x - 1)^{2} + 3 x (x + 2) : 4 x^{2} + 4 x + 1

4 x^{2} + 4 x + 1 = 4 x^{2} + 4 x + 1

Move

1

to the right side

4 x^{2} + 4 x = 4 x^{2} + 4 x

Subtract

4 x^{2} + 4 x

from both sides

4 x^{2} + 4 x - (4 x^{2} + 4 x) = 4 x^{2} + 4 x - (4 x^{2} + 4 x)

Simplify

0 = 0

Both sides are equal

True for all x

4^{3} \cdot x^{2} \cdot (\frac{4}{x})^{- 2}

- 5 x - 9 \leq - \frac{3 x}{2}

\frac{5}{4} + \frac{3}{4}

3 (v + 2) - v = 2 (v - 1) + 5

y^{2} - 8 y = - 14

What is the answer to (2x+1)^2=(x-1)^2+3x(x+2) ?
The answer to (2x+1)^2=(x-1)^2+3x(x+2) is True for all x
Solve for x: (2x+1)^2=(x-1)^2+3x(x+2)
The solution is True for all x