What are the solutions to the equation x^2+10x+12=0 ?

The solutions to the equation x^2+10x+12=0 are x=-5+sqrt(13),x=-5-sqrt(13)

Find the zeros of x^2+10x+12=0

The zeros of x^2+10x+12=0 are x=-5+sqrt(13),x=-5-sqrt(13)

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x^{2} + 10 x + 12 = 0

x = - 5 + 13, x = - 5 - 13

Decimal Notation

x = - 1.39444 \dots, x = - 8.60555 \dots

Solution steps

x^{2} + 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 12 = 213

x_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 13}{2 \cdot 1}

x = \frac{- 10 + 2 13}{2 \cdot 1} : - 5 + 13

x = \frac{- 10 - 2 13}{2 \cdot 1} : - 5 - 13

The solutions to the quadratic equation are:

x = - 5 + 13, x = - 5 - 13

3 (3 y - 4) = 33

\frac{r}{x y} (x m + y m + x y k)

5 + 2 x \geq 1 - (- x + \frac{5}{2})

w^{2} - 150 w + 2100 = 0

2 x^{3} + x^{2} - 18 x - 9

What are the solutions to the equation x^2+10x+12=0 ?
The solutions to the equation x^2+10x+12=0 are x=-5+sqrt(13),x=-5-sqrt(13)
Find the zeros of x^2+10x+12=0
The zeros of x^2+10x+12=0 are x=-5+sqrt(13),x=-5-sqrt(13)