What are the solutions to the equation w^2-150w+2100=0 ?

The solutions to the equation w^2-150w+2100=0 are w=5(15+sqrt(141)),w=5(15-sqrt(141))

Find the zeros of w^2-150w+2100=0

The zeros of w^2-150w+2100=0 are w=5(15+sqrt(141)),w=5(15-sqrt(141))

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w^{2} - 150 w + 2100 = 0

w = 5 (15 + 141), w = 5 (15 - 141)

Solution steps

w^{2} - 150 w + 2100 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 150 ) \pm ( - 150 ) ^{2} - 4 \cdot 1 \cdot 2100}{2 \cdot 1}

(- 150)^{2} - 4 \cdot 1 \cdot 2100 = 10141

w_{1, 2} = \frac{- ( - 150 ) \pm 10 141}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 150 ) + 10 141}{2 \cdot 1}, w_{2} = \frac{- ( - 150 ) - 10 141}{2 \cdot 1}

w = \frac{- ( - 150 ) + 10 141}{2 \cdot 1} : 5 (15 + 141)

w = \frac{- ( - 150 ) - 10 141}{2 \cdot 1} : 5 (15 - 141)

The solutions to the quadratic equation are:

w = 5 (15 + 141), w = 5 (15 - 141)

2 x^{3} + x^{2} - 18 x - 9

x (x - 8) = - 15

5 \cdot 17

(- 32)^{\frac{2}{5}}

x^{2} - 4 x - 5

What are the solutions to the equation w^2-150w+2100=0 ?
The solutions to the equation w^2-150w+2100=0 are w=5(15+sqrt(141)),w=5(15-sqrt(141))
Find the zeros of w^2-150w+2100=0
The zeros of w^2-150w+2100=0 are w=5(15+sqrt(141)),w=5(15-sqrt(141))