What are the solutions to the equation (x-5)^2=17 ?

The solutions to the equation (x-5)^2=17 are x=sqrt(17)+5,x=-sqrt(17)+5

Find the zeros of (x-5)^2=17

The zeros of (x-5)^2=17 are x=sqrt(17)+5,x=-sqrt(17)+5

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(x - 5)^{2} = 17

x = 17 + 5, x = - 17 + 5

Solution steps

(x - 5)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 17 : x = 17 + 5

Solve

x - 5 = - 17 : x = - 17 + 5

The solutions to the quadratic equation are:

x = 17 + 5, x = - 17 + 5

∣ 5 x + 3 ∣ = 17

36 y^{2} - 1

\frac{1.4}{3} (1.3 + 4 (1.6) + 2 (1.8) + 4 (1.9) + 2 (2.2) + 4 (2.3) + 2.1)

(x^{2} - 16)^{2}

(\frac{39}{2})^{2} - (\frac{15}{2})^{2} = x^{2}

What are the solutions to the equation (x-5)^2=17 ?
The solutions to the equation (x-5)^2=17 are x=sqrt(17)+5,x=-sqrt(17)+5
Find the zeros of (x-5)^2=17
The zeros of (x-5)^2=17 are x=sqrt(17)+5,x=-sqrt(17)+5