What are the solutions to the equation (39/2)^2-(15/2)^2=x^2 ?

The solutions to the equation (39/2)^2-(15/2)^2=x^2 are x=18,x=-18

Find the zeros of (39/2)^2-(15/2)^2=x^2

The zeros of (39/2)^2-(15/2)^2=x^2 are x=18,x=-18

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(\frac{39}{2})^{2} - (\frac{15}{2})^{2} = x^{2}

x = 18, x = - 18

Solution steps

(\frac{39}{2})^{2} - (\frac{15}{2})^{2} = x^{2}

Switch sides

x^{2} = (\frac{39}{2})^{2} - (\frac{15}{2})^{2}

Simplify

(\frac{39}{2})^{2} - (\frac{15}{2})^{2} : 324

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 324, x = - 324

324 = 18

- 324 = - 18

x = 18, x = - 18

\frac{( - 3 ) ^{2} - 2 x - 4}{- 2} > - 4

\frac{x + 1}{x - 1} < 2

(x - 5) (x - 12) = 44

t^{2} - 21 t = 0

6 n^{4} + 20 n^{3} + 14 n^{2}

What are the solutions to the equation (39/2)^2-(15/2)^2=x^2 ?
The solutions to the equation (39/2)^2-(15/2)^2=x^2 are x=18,x=-18
Find the zeros of (39/2)^2-(15/2)^2=x^2
The zeros of (39/2)^2-(15/2)^2=x^2 are x=18,x=-18