What are the solutions to the equation (x-5)(x-12)=44 ?

The solutions to the equation (x-5)(x-12)=44 are x=16,x=1

Find the zeros of (x-5)(x-12)=44

The zeros of (x-5)(x-12)=44 are x=16,x=1

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(x - 5) (x - 12) = 44

x = 16, x = 1

Solution steps

(x - 5) (x - 12) = 44

Expand

(x - 5) (x - 12) : x^{2} - 17 x + 60

x^{2} - 17 x + 60 = 44

Move

44

to the left side

x^{2} - 17 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 16 = 15

x_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 1}

x = \frac{- ( - 17 ) + 15}{2 \cdot 1} : 16

x = \frac{- ( - 17 ) - 15}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 16, x = 1

t^{2} - 21 t = 0

6 n^{4} + 20 n^{3} + 14 n^{2}

- 9 e^{- 0} + C = 0

\frac{\frac{2}{x} - y x}{\frac{1}{y} + \frac{1}{x ^{2}}}

\frac{2}{3}

What are the solutions to the equation (x-5)(x-12)=44 ?
The solutions to the equation (x-5)(x-12)=44 are x=16,x=1
Find the zeros of (x-5)(x-12)=44
The zeros of (x-5)(x-12)=44 are x=16,x=1