What are the solutions to the equation 5x=x^2-6 ?

The solutions to the equation 5x=x^2-6 are x=6,x=-1

Find the zeros of 5x=x^2-6

The zeros of 5x=x^2-6 are x=6,x=-1

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5 x = x^{2} - 6

x = 6, x = - 1

Solution steps

5 x = x^{2} - 6

Switch sides

x^{2} - 6 = 5 x

Move

5 x

to the left side

x^{2} - 6 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

(j^{- 13}) (j^{4}) (j^{6})

9 x^{2} - 9

4 - 3 (- 6 n - 2)

\frac{( - 5 a ^{4} b ^{3} c )}{( - a ^{2} b )}

3 x^{2} + 12 x + 12

What are the solutions to the equation 5x=x^2-6 ?
The solutions to the equation 5x=x^2-6 are x=6,x=-1
Find the zeros of 5x=x^2-6
The zeros of 5x=x^2-6 are x=6,x=-1