What are the solutions to the equation 6^2+b^2=8^2 ?

The solutions to the equation 6^2+b^2=8^2 are b=2sqrt(7),b=-2sqrt(7)

Find the zeros of 6^2+b^2=8^2

The zeros of 6^2+b^2=8^2 are b=2sqrt(7),b=-2sqrt(7)

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6^{2} + b^{2} = 8^{2}

b = 27, b = - 27

Decimal Notation

b = 5.29150 \dots, b = - 5.29150 \dots

Solution steps

6^{2} + b^{2} = 8^{2}

Move

6^{2}

to the right side

b^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 28, b = - 28

28 = 27

- 28 = - 27

b = 27, b = - 27

0 = 4 x + 1

3 (y - 5) + 2 = 5

\frac{12 a x y}{- 2 a x y}

x^{2} - 16 x + 62 = 0

49 x^{2} - 64 y^{2}

What are the solutions to the equation 6^2+b^2=8^2 ?
The solutions to the equation 6^2+b^2=8^2 are b=2sqrt(7),b=-2sqrt(7)
Find the zeros of 6^2+b^2=8^2
The zeros of 6^2+b^2=8^2 are b=2sqrt(7),b=-2sqrt(7)