What are the solutions to the equation 16x^2+16x+4=0 ?

The solutions to the equation 16x^2+16x+4=0 are x=-1/2

Find the zeros of 16x^2+16x+4=0

The zeros of 16x^2+16x+4=0 are x=-1/2

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16 x^{2} + 16 x + 4 = 0

x = - \frac{1}{2}

Solution steps

16 x^{2} + 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 16 \cdot 4}{2 \cdot 16}

1 6^{2} - 4 \cdot 16 \cdot 4 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 16}

x = \frac{- 16}{2 \cdot 16}

\frac{- 16}{2 \cdot 16} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

3 t^{2} - 5 t - 9 = 0

lo g_{100} (10) = x

\frac{9}{16} = \frac{x}{12}

∣ x - 2 ∣ \geq 4

\frac{3 π}{2} + \frac{π}{4}

What are the solutions to the equation 16x^2+16x+4=0 ?
The solutions to the equation 16x^2+16x+4=0 are x=-1/2
Find the zeros of 16x^2+16x+4=0
The zeros of 16x^2+16x+4=0 are x=-1/2