What are the solutions to the equation 3x^2+11x+10=0 ?

The solutions to the equation 3x^2+11x+10=0 are x=-5/3 ,x=-2

Find the zeros of 3x^2+11x+10=0

The zeros of 3x^2+11x+10=0 are x=-5/3 ,x=-2

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3 x^{2} + 11 x + 10 = 0

x = - \frac{5}{3}, x = - 2

Solution steps

3 x^{2} + 11 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 10 = 1

x_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 1}{2 \cdot 3}, x_{2} = \frac{- 11 - 1}{2 \cdot 3}

x = \frac{- 11 + 1}{2 \cdot 3} : - \frac{5}{3}

x = \frac{- 11 - 1}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - 2

x^{2} - 48 = 2 x

x + \frac{13}{30} = - \frac{7}{30}

x^{4} + 2 x > 2 x^{3} + x^{2}

p - 8 > 1

27 + 8 y^{3}

What are the solutions to the equation 3x^2+11x+10=0 ?
The solutions to the equation 3x^2+11x+10=0 are x=-5/3 ,x=-2
Find the zeros of 3x^2+11x+10=0
The zeros of 3x^2+11x+10=0 are x=-5/3 ,x=-2