What are the solutions to the equation m^2+8m+16=45 ?

The solutions to the equation m^2+8m+16=45 are m=-4+3sqrt(5),m=-4-3sqrt(5)

Find the zeros of m^2+8m+16=45

The zeros of m^2+8m+16=45 are m=-4+3sqrt(5),m=-4-3sqrt(5)

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m^{2} + 8 m + 16 = 45

m = - 4 + 35, m = - 4 - 35

Decimal Notation

m = 2.70820 \dots, m = - 10.70820 \dots

Solution steps

m^{2} + 8 m + 16 = 45

Move

45

to the left side

m^{2} + 8 m - 29 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 29 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 29) = 65

m_{1, 2} = \frac{- 8 \pm 6 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 6 5}{2 \cdot 1}, m_{2} = \frac{- 8 - 6 5}{2 \cdot 1}

m = \frac{- 8 + 6 5}{2 \cdot 1} : - 4 + 35

m = \frac{- 8 - 6 5}{2 \cdot 1} : - 4 - 35

The solutions to the quadratic equation are:

m = - 4 + 35, m = - 4 - 35

x^{- \frac{1}{3}}

c^{2} + 66 c - 67

6 x^{3} - 5 x^{2} - 12 x - 4

4 a^{2} - 9 c^{2}

- 2 x + 5 > 11

What are the solutions to the equation m^2+8m+16=45 ?
The solutions to the equation m^2+8m+16=45 are m=-4+3sqrt(5),m=-4-3sqrt(5)
Find the zeros of m^2+8m+16=45
The zeros of m^2+8m+16=45 are m=-4+3sqrt(5),m=-4-3sqrt(5)