What are the solutions to the equation 2w^2-w=6 ?

The solutions to the equation 2w^2-w=6 are w=2,w=-3/2

Find the zeros of 2w^2-w=6

The zeros of 2w^2-w=6 are w=2,w=-3/2

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2 w^{2} - w = 6

w = 2, w = - \frac{3}{2}

Solution steps

2 w^{2} - w = 6

Move

6

to the left side

2 w^{2} - w - 6 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

w_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, w_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

w = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

w = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

w = 2, w = - \frac{3}{2}

(t + 3)^{2} = 5

x^{2} - 2 x - 3 = 4

(6 k^{4}) (- k^{2})

\frac{19 - 4 i}{2 - 5 i} + \frac{3 + 2 i}{i}

6 x^{2} - 55 x + 9

What are the solutions to the equation 2w^2-w=6 ?
The solutions to the equation 2w^2-w=6 are w=2,w=-3/2
Find the zeros of 2w^2-w=6
The zeros of 2w^2-w=6 are w=2,w=-3/2