What are the solutions to the equation v^2=4 ?

The solutions to the equation v^2=4 are v=2,v=-2

Find the zeros of v^2=4

The zeros of v^2=4 are v=2,v=-2

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v^{2} = 4

v = 2, v = - 2

Solution steps

v^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 4, v = - 4

4 = 2

- 4 = - 2

v = 2, v = - 2

x^{2} + 14 x + 17 = - 96

\frac{5 π}{12} - \frac{π}{4}

8 x + 9 \leq 16 x - 13

6 + 5 x = 9 x - 4 + 6 x

What are the solutions to the equation v^2=4 ?
The solutions to the equation v^2=4 are v=2,v=-2
Find the zeros of v^2=4
The zeros of v^2=4 are v=2,v=-2