What are the solutions to the equation x^2+4-1=0 ?

The solutions to the equation x^2+4-1=0 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^2+4-1=0

The zeros of x^2+4-1=0 are x=sqrt(3)i,x=-sqrt(3)i

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x^{2} + 4 - 1 = 0

x = 3 i, x = - 3 i

Solution steps

x^{2} + 4 - 1 = 0

Move

4

to the right side

x^{2} - 1 = - 4

Move

1

to the right side

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

x^{2} - 81 < 0

r^{2} - 3 r - 54 = 0

2 k^{2} + 7 k + 6

(x + 6)^{2} = - 25

(5^{\frac{1}{2}})^{2}

What are the solutions to the equation x^2+4-1=0 ?
The solutions to the equation x^2+4-1=0 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^2+4-1=0
The zeros of x^2+4-1=0 are x=sqrt(3)i,x=-sqrt(3)i