What are the solutions to the equation x^2-26x+169=-13 ?

The solutions to the equation x^2-26x+169=-13 are x=13+sqrt(13)i,x=13-sqrt(13)i

Find the zeros of x^2-26x+169=-13

The zeros of x^2-26x+169=-13 are x=13+sqrt(13)i,x=13-sqrt(13)i

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x^{2} - 26 x + 169 = - 13

x = 13 + 13 i, x = 13 - 13 i

Solution steps

x^{2} - 26 x + 169 = - 13

Move

13

to the left side

x^{2} - 26 x + 182 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 182}{2 \cdot 1}

Simplify

(- 26)^{2} - 4 \cdot 1 \cdot 182 : 213 i

x_{1, 2} = \frac{- ( - 26 ) \pm 2 13 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 2 13 i}{2 \cdot 1}, x_{2} = \frac{- ( - 26 ) - 2 13 i}{2 \cdot 1}

x = \frac{- ( - 26 ) + 2 13 i}{2 \cdot 1} : 13 + 13 i

x = \frac{- ( - 26 ) - 2 13 i}{2 \cdot 1} : 13 - 13 i

The solutions to the quadratic equation are:

x = 13 + 13 i, x = 13 - 13 i

99 - 13 (2 X - 10) = 4 (5 X - 9) - 5025

x^{2} - 2 x + \frac{2}{3} = 0

x^{2} = 11

3 x^{- 4}

6 (2 x - 1) - 12 = - 2 (x + 10)

What are the solutions to the equation x^2-26x+169=-13 ?
The solutions to the equation x^2-26x+169=-13 are x=13+sqrt(13)i,x=13-sqrt(13)i
Find the zeros of x^2-26x+169=-13
The zeros of x^2-26x+169=-13 are x=13+sqrt(13)i,x=13-sqrt(13)i