What are the solutions to the equation 3x^2+6x-2=0 ?

The solutions to the equation 3x^2+6x-2=0 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3

Find the zeros of 3x^2+6x-2=0

The zeros of 3x^2+6x-2=0 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3

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3 x^{2} + 6 x - 2 = 0

x = \frac{- 3 + 15}{3}, x = - \frac{3 + 15}{3}

Decimal Notation

x = 0.29099 \dots, x = - 2.29099 \dots

Solution steps

3 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 2) = 215

x_{1, 2} = \frac{- 6 \pm 2 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 15}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 15}{2 \cdot 3}

x = \frac{- 6 + 2 15}{2 \cdot 3} : \frac{- 3 + 15}{3}

x = \frac{- 6 - 2 15}{2 \cdot 3} : - \frac{3 + 15}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 15}{3}, x = - \frac{3 + 15}{3}

- 71 + 4 x \leq - 87

4! \cdot 4!

x + \frac{13}{12} = \frac{11}{12} x

4 > 7 x + 9

9 x^{2} - 3 x + 2 = 0

What are the solutions to the equation 3x^2+6x-2=0 ?
The solutions to the equation 3x^2+6x-2=0 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3
Find the zeros of 3x^2+6x-2=0
The zeros of 3x^2+6x-2=0 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3