What are the solutions to the equation -2x^2+4=0 ?

The solutions to the equation -2x^2+4=0 are x=sqrt(2),x=-sqrt(2)

Find the zeros of -2x^2+4=0

The zeros of -2x^2+4=0 are x=sqrt(2),x=-sqrt(2)

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- 2 x^{2} + 4 = 0

x = 2, x = - 2

Solution steps

- 2 x^{2} + 4 = 0

Move

4

to the right side

- 2 x^{2} = - 4

Divide both sides by

- 2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

\frac{4}{3} \cdot \frac{4}{3} \cdot \frac{4}{3}

2 m^{2} - 50

90 = s + \frac{s ^{2}}{10}

- x + 4 < \frac{1}{2} x + 1

8 n^{2} + 16 n + 15 = 9

What are the solutions to the equation -2x^2+4=0 ?
The solutions to the equation -2x^2+4=0 are x=sqrt(2),x=-sqrt(2)
Find the zeros of -2x^2+4=0
The zeros of -2x^2+4=0 are x=sqrt(2),x=-sqrt(2)