What are the solutions to the equation 90=s+(s^2)/(10) ?

The solutions to the equation 90=s+(s^2)/(10) are s=5(sqrt(37)-1),s=-5(1+sqrt(37))

Find the zeros of 90=s+(s^2)/(10)

The zeros of 90=s+(s^2)/(10) are s=5(sqrt(37)-1),s=-5(1+sqrt(37))

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90 = s + \frac{s ^{2}}{10}

s = 5 (37 - 1), s = - 5 (1 + 37)

Solution steps

90 = s + \frac{s ^{2}}{10}

Multiply both sides by

10

900 = 10 s + s^{2}

Switch sides

10 s + s^{2} = 900

Move

900

to the left side

10 s + s^{2} - 900 = 0

Write in the standard form

a x^{2} + b x + c = 0

s^{2} + 10 s - 900 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 900 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 900) = 1037

s_{1, 2} = \frac{- 10 \pm 10 37}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 10 + 10 37}{2 \cdot 1}, s_{2} = \frac{- 10 - 10 37}{2 \cdot 1}

s = \frac{- 10 + 10 37}{2 \cdot 1} : 5 (37 - 1)

s = \frac{- 10 - 10 37}{2 \cdot 1} : - 5 (1 + 37)

The solutions to the quadratic equation are:

s = 5 (37 - 1), s = - 5 (1 + 37)

- x + 4 < \frac{1}{2} x + 1

8 n^{2} + 16 n + 15 = 9

- x^{2} + 5 x

\frac{8 ( - m ^{0} n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} n ^{0} ( - 2 m ^{- 2} n ^{4} ) ^{3}}

x^{3} + 4 x^{2} < 4 x + 16

What are the solutions to the equation 90=s+(s^2)/(10) ?
The solutions to the equation 90=s+(s^2)/(10) are s=5(sqrt(37)-1),s=-5(1+sqrt(37))
Find the zeros of 90=s+(s^2)/(10)
The zeros of 90=s+(s^2)/(10) are s=5(sqrt(37)-1),s=-5(1+sqrt(37))