What are the solutions to the equation x^2+11x-5=0 ?

The solutions to the equation x^2+11x-5=0 are x=(-11+sqrt(141))/2 ,x=(-11-sqrt(141))/2

Find the zeros of x^2+11x-5=0

The zeros of x^2+11x-5=0 are x=(-11+sqrt(141))/2 ,x=(-11-sqrt(141))/2

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x^{2} + 11 x - 5 = 0

x = \frac{- 11 + 141}{2}, x = \frac{- 11 - 141}{2}

Decimal Notation

x = 0.43717 \dots, x = - 11.43717 \dots

Solution steps

x^{2} + 11 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 5) = 141

x_{1, 2} = \frac{- 11 \pm 141}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 141}{2 \cdot 1}, x_{2} = \frac{- 11 - 141}{2 \cdot 1}

x = \frac{- 11 + 141}{2 \cdot 1} : \frac{- 11 + 141}{2}

x = \frac{- 11 - 141}{2 \cdot 1} : \frac{- 11 - 141}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 141}{2}, x = \frac{- 11 - 141}{2}

x^{2} + 3 x^{2} + 4

a^{3} - 2 a^{2} + 2 a - 4

∣ x + 4 ∣^{2} - 10 ∣ x + 4 ∣ = 24

2 x^{2} + 11 x + 14 = 0

16 - 8

What are the solutions to the equation x^2+11x-5=0 ?
The solutions to the equation x^2+11x-5=0 are x=(-11+sqrt(141))/2 ,x=(-11-sqrt(141))/2
Find the zeros of x^2+11x-5=0
The zeros of x^2+11x-5=0 are x=(-11+sqrt(141))/2 ,x=(-11-sqrt(141))/2