What are the solutions to the equation 3x^2+9x-1=0 ?

The solutions to the equation 3x^2+9x-1=0 are x=(-9+sqrt(93))/6 ,x=(-9-sqrt(93))/6

Find the zeros of 3x^2+9x-1=0

The zeros of 3x^2+9x-1=0 are x=(-9+sqrt(93))/6 ,x=(-9-sqrt(93))/6

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3 x^{2} + 9 x - 1 = 0

x = \frac{- 9 + 93}{6}, x = \frac{- 9 - 93}{6}

Decimal Notation

x = 0.10727 \dots, x = - 3.10727 \dots

Solution steps

3 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 1) = 93

x_{1, 2} = \frac{- 9 \pm 93}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 93}{2 \cdot 3}, x_{2} = \frac{- 9 - 93}{2 \cdot 3}

x = \frac{- 9 + 93}{2 \cdot 3} : \frac{- 9 + 93}{6}

x = \frac{- 9 - 93}{2 \cdot 3} : \frac{- 9 - 93}{6}

The solutions to the quadratic equation are:

x = \frac{- 9 + 93}{6}, x = \frac{- 9 - 93}{6}

- \frac{3}{2} (2)

\frac{1}{4} + \frac{1}{4} + \frac{1}{4} + \frac{1}{4}

1 - 0.55

(3 x - 2) (x + 4) - 3 (x + 5) (x - 1) = 0

2 x - 14 = 7 x + 6

What are the solutions to the equation 3x^2+9x-1=0 ?
The solutions to the equation 3x^2+9x-1=0 are x=(-9+sqrt(93))/6 ,x=(-9-sqrt(93))/6
Find the zeros of 3x^2+9x-1=0
The zeros of 3x^2+9x-1=0 are x=(-9+sqrt(93))/6 ,x=(-9-sqrt(93))/6