What are the solutions to the equation 3x^2-12x=-12 ?

The solutions to the equation 3x^2-12x=-12 are x=2

Find the zeros of 3x^2-12x=-12

The zeros of 3x^2-12x=-12 are x=2

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3 x^{2} - 12 x = - 12

x = 2

Solution steps

3 x^{2} - 12 x = - 12

Move

12

to the left side

3 x^{2} - 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 12 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 3}

x = \frac{- ( - 12 )}{2 \cdot 3}

\frac{- ( - 12 )}{2 \cdot 3} = 2

x = 2

The solution to the quadratic equation is:

x = 2

3 x^{2} - 26 x + 11 = - 5

\frac{- 4 y ^{- 2}}{8 x ^{- 2}}

\frac{1}{2} + \frac{3}{4}

\frac{35 x ^{3} y ^{8}}{14 x ^{2} y ^{3}}

x + 6 = - 7

What are the solutions to the equation 3x^2-12x=-12 ?
The solutions to the equation 3x^2-12x=-12 are x=2
Find the zeros of 3x^2-12x=-12
The zeros of 3x^2-12x=-12 are x=2