What are the solutions to the equation x^2+2=3 ?

The solutions to the equation x^2+2=3 are x=1,x=-1

Find the zeros of x^2+2=3

The zeros of x^2+2=3 are x=1,x=-1

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x^{2} + 2 = 3

x = 1, x = - 1

Solution steps

x^{2} + 2 = 3

Move

2

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

6 x - 5 = 3

2 z^{2} = 13 z + 15

\frac{5 a ^{7}}{10 a ^{3}}

12 (p^{2} - 1) = 7 p

6^{- 7}

What are the solutions to the equation x^2+2=3 ?
The solutions to the equation x^2+2=3 are x=1,x=-1
Find the zeros of x^2+2=3
The zeros of x^2+2=3 are x=1,x=-1