What are the solutions to the equation -2x^2-8x-4=0 ?

The solutions to the equation -2x^2-8x-4=0 are x=-2-sqrt(2),x=-2+sqrt(2)

Find the zeros of -2x^2-8x-4=0

The zeros of -2x^2-8x-4=0 are x=-2-sqrt(2),x=-2+sqrt(2)

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- 2 x^{2} - 8 x - 4 = 0

x = - 2 - 2, x = - 2 + 2

Decimal Notation

x = - 3.41421 \dots, x = - 0.58578 \dots

Solution steps

- 2 x^{2} - 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

(- 8)^{2} - 4 (- 2) (- 4) = 42

x_{1, 2} = \frac{- ( - 8 ) \pm 4 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 4 2}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 4 2}{2 ( - 2 )} : - 2 - 2

x = \frac{- ( - 8 ) - 4 2}{2 ( - 2 )} : - 2 + 2

The solutions to the quadratic equation are:

x = - 2 - 2, x = - 2 + 2

∣ - 2 x ∣ = 10

4 x^{3} - 36 x^{2} + 8 x + 192 > 0

\frac{a}{b} + \frac{b}{a}

3 x^{2} - 18 x + 12 = 0

2 (2 x - 9) \leq 6

What are the solutions to the equation -2x^2-8x-4=0 ?
The solutions to the equation -2x^2-8x-4=0 are x=-2-sqrt(2),x=-2+sqrt(2)
Find the zeros of -2x^2-8x-4=0
The zeros of -2x^2-8x-4=0 are x=-2-sqrt(2),x=-2+sqrt(2)