What are the solutions to the equation 3x^2-18x+12=0 ?

The solutions to the equation 3x^2-18x+12=0 are x=3+sqrt(5),x=3-sqrt(5)

Find the zeros of 3x^2-18x+12=0

The zeros of 3x^2-18x+12=0 are x=3+sqrt(5),x=3-sqrt(5)

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3 x^{2} - 18 x + 12 = 0

x = 3 + 5, x = 3 - 5

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

3 x^{2} - 18 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 12 = 65

x_{1, 2} = \frac{- ( - 18 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 18 ) + 6 5}{2 \cdot 3} : 3 + 5

x = \frac{- ( - 18 ) - 6 5}{2 \cdot 3} : 3 - 5

The solutions to the quadratic equation are:

x = 3 + 5, x = 3 - 5

2 (2 x - 9) \leq 6

(- 5 x - 1) (2 x + 8) = 0

(x + 9) (x - 9) = 0

y^{10}

What are the solutions to the equation 3x^2-18x+12=0 ?
The solutions to the equation 3x^2-18x+12=0 are x=3+sqrt(5),x=3-sqrt(5)
Find the zeros of 3x^2-18x+12=0
The zeros of 3x^2-18x+12=0 are x=3+sqrt(5),x=3-sqrt(5)