What are the solutions to the equation 17^2+22^2=x^2 ?

The solutions to the equation 17^2+22^2=x^2 are x=sqrt(773),x=-sqrt(773)

Find the zeros of 17^2+22^2=x^2

The zeros of 17^2+22^2=x^2 are x=sqrt(773),x=-sqrt(773)

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1 7^{2} + 2 2^{2} = x^{2}

x = 773, x = - 773

Decimal Notation

x = 27.80287 \dots, x = - 27.80287 \dots

Solution steps

1 7^{2} + 2 2^{2} = x^{2}

Switch sides

x^{2} = 1 7^{2} + 2 2^{2}

Simplify

1 7^{2} + 2 2^{2} : 773

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 773, x = - 773

\frac{3 π}{2} \cdot 2

x^{2} - 2 x - 13 = 0

\frac{1}{81} < 9^{2 x - 4}

∣ 2 - 3 x ∣ + 3 < 8

7 x - 35 < 2 (x - 5)

What are the solutions to the equation 17^2+22^2=x^2 ?
The solutions to the equation 17^2+22^2=x^2 are x=sqrt(773),x=-sqrt(773)
Find the zeros of 17^2+22^2=x^2
The zeros of 17^2+22^2=x^2 are x=sqrt(773),x=-sqrt(773)