What are the solutions to the equation x^2=3x+40 ?

The solutions to the equation x^2=3x+40 are x=8,x=-5

Find the zeros of x^2=3x+40

The zeros of x^2=3x+40 are x=8,x=-5

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x^{2} = 3 x + 40

x = 8, x = - 5

Solution steps

x^{2} = 3 x + 40

Move

40

to the left side

x^{2} - 40 = 3 x

Move

3 x

to the left side

x^{2} - 40 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

x = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

x = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 8, x = - 5

2 x^{2} = x + 15

3 y^{2} - 3 y - 90

\frac{( 2 \cdot 3 - 1 ) ( 2 \cdot 3 - 3 ) ( 2 \cdot 3 - 5 )}{2 ^{3}}

49 x^{2} - 144 y^{4}

18 - 50 w^{2}

What are the solutions to the equation x^2=3x+40 ?
The solutions to the equation x^2=3x+40 are x=8,x=-5
Find the zeros of x^2=3x+40
The zeros of x^2=3x+40 are x=8,x=-5