What are the solutions to the equation -x^2+x-6=0 ?

The solutions to the equation -x^2+x-6=0 are x= 1/2-i(sqrt(23))/2 ,x= 1/2+i(sqrt(23))/2

Find the zeros of -x^2+x-6=0

The zeros of -x^2+x-6=0 are x= 1/2-i(sqrt(23))/2 ,x= 1/2+i(sqrt(23))/2

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- x^{2} + x - 6 = 0

x = \frac{1}{2} - i \frac{23}{2}, x = \frac{1}{2} + i \frac{23}{2}

Solution steps

- x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 6) : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 23 i}{2 ( - 1 )}

x = \frac{- 1 + 23 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{23}{2}

x = \frac{- 1 - 23 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{23}{2}, x = \frac{1}{2} + i \frac{23}{2}

n^{2} - 2 n - 61 = - 7

(- 0.2)^{2}

4 x^{2} - 8 x + 7 = 0

5 u \leq 8 u - 21

x - 9 \leq - 8

What are the solutions to the equation -x^2+x-6=0 ?
The solutions to the equation -x^2+x-6=0 are x= 1/2-i(sqrt(23))/2 ,x= 1/2+i(sqrt(23))/2
Find the zeros of -x^2+x-6=0
The zeros of -x^2+x-6=0 are x= 1/2-i(sqrt(23))/2 ,x= 1/2+i(sqrt(23))/2