What are the solutions to the equation x^2+x-6=0 ?

The solutions to the equation x^2+x-6=0 are x=2,x=-3

Find the zeros of x^2+x-6=0

The zeros of x^2+x-6=0 are x=2,x=-3

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x^{2} + x - 6 = 0

x = 2, x = - 3

Solution steps

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

2 x^{2} + 20

u^{2} - 36

w^{6}

- x^{2} + 8 x - 16 = 0

x^{4} + 15 x^{2} + 56

What are the solutions to the equation x^2+x-6=0 ?
The solutions to the equation x^2+x-6=0 are x=2,x=-3
Find the zeros of x^2+x-6=0
The zeros of x^2+x-6=0 are x=2,x=-3