What is the answer to (7x)/3+13/2-(7x)/6 = 17/12-(3x)/4 ?

The answer to (7x)/3+13/2-(7x)/6 = 17/12-(3x)/4 is x=-61/23

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(7x)/3+13/2-(7x)/6 = 17/12-(3x)/4

\frac{7 x}{3} + \frac{13}{2} - \frac{7 x}{6} = \frac{17}{12} - \frac{3 x}{4}

x = - \frac{61}{23}

Decimal Notation

x = - 2.65217 \dots

Solution steps

\frac{7 x}{3} + \frac{13}{2} - \frac{7 x}{6} = \frac{17}{12} - \frac{3 x}{4}

Move

\frac{3 x}{4}

to the left side

\frac{13}{2} + \frac{23 x}{12} = \frac{17}{12}

Move

\frac{13}{2}

to the right side

\frac{23 x}{12} = - \frac{61}{12}

Multiply both sides by

12

23 x = - 61

Divide both sides by

23

x = - \frac{61}{23}

- 2 = x + 14

\frac{- 36}{12}

3 (- \frac{5}{6} y - \frac{32}{6}) - 4 y = - 29

(- \frac{1}{2}) - 1

s^{2} - 4 s + 20 = 0

What is the answer to (7x)/3+13/2-(7x)/6 = 17/12-(3x)/4 ?
The answer to (7x)/3+13/2-(7x)/6 = 17/12-(3x)/4 is x=-61/23
Solve for x: (7x)/3+13/2-(7x)/6 = 17/12-(3x)/4
The solution is x=-61/23