What are the solutions to the equation 3x^2-2x+10=0 ?

The solutions to the equation 3x^2-2x+10=0 are x= 1/3+i(sqrt(29))/3 ,x= 1/3-i(sqrt(29))/3

Find the zeros of 3x^2-2x+10=0

The zeros of 3x^2-2x+10=0 are x= 1/3+i(sqrt(29))/3 ,x= 1/3-i(sqrt(29))/3

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3 x^{2} - 2 x + 10 = 0

x = \frac{1}{3} + i \frac{29}{3}, x = \frac{1}{3} - i \frac{29}{3}

Solution steps

3 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 10 : 229 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 29 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 29 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 29 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 29 i}{2 \cdot 3} : \frac{1}{3} + i \frac{29}{3}

x = \frac{- ( - 2 ) - 2 29 i}{2 \cdot 3} : \frac{1}{3} - i \frac{29}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{29}{3}, x = \frac{1}{3} - i \frac{29}{3}

2 x^{2} - 16 x + 24 = 0

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2^{- 4}

\frac{5 p}{2 q - p} + \frac{10 p}{p - 2 q}

- 76 x + 76 = 76 x + 76

What are the solutions to the equation 3x^2-2x+10=0 ?
The solutions to the equation 3x^2-2x+10=0 are x= 1/3+i(sqrt(29))/3 ,x= 1/3-i(sqrt(29))/3
Find the zeros of 3x^2-2x+10=0
The zeros of 3x^2-2x+10=0 are x= 1/3+i(sqrt(29))/3 ,x= 1/3-i(sqrt(29))/3