What is (12x^6y^{-4}z^2)/(3x^2y^{-6)z^3} ?

The solution to (12x^6y^{-4}z^2)/(3x^2y^{-6)z^3} is (4x^4y^2)/z

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simplify (12x^6y^{-4}z^2)/(3x^2y^{-6)z^3}

simplify

\frac{12 x ^{6} y ^{- 4} z ^{2}}{3 x ^{2} y ^{- 6} z ^{3}}

\frac{4 x ^{4} y ^{2}}{z}

Solution steps

\frac{12 x ^{6} y ^{- 4} z ^{2}}{3 x ^{2} y ^{- 6} z ^{3}}

Factor the number:

12 = 3 \cdot 4

= \frac{3 \cdot 4 x ^{6} y ^{- 4} z ^{2}}{3 x ^{2} y ^{- 6} z ^{3}}

Cancel the common factor:

3

= \frac{4 x ^{6} y ^{- 4} z ^{2}}{x ^{2} y ^{- 6} z ^{3}}

Simplify

\frac{x ^{6}}{x ^{2}} : x^{4}

= \frac{4 x ^{4} y ^{- 4} z ^{2}}{y ^{- 6} z ^{3}}

Simplify

\frac{y ^{- 4}}{y ^{- 6}} : y^{2}

= \frac{4 x ^{4} y ^{2} z ^{2}}{z ^{3}}

Simplify

\frac{z ^{2}}{z ^{3}} : \frac{1}{z}

= \frac{4 x ^{4} y ^{2}}{z}

\frac{1}{16} x^{4} + 4 x^{2} + 64

\frac{1}{2} x^{2} + 3 x - 3.5

i

x (x - 2) = 0

- 2 ∣ x + 3 ∣ + 10 = - 4

What is (12x^6y^{-4}z^2)/(3x^2y^{-6)z^3} ?
The solution to (12x^6y^{-4}z^2)/(3x^2y^{-6)z^3} is (4x^4y^2)/z