What are the solutions to the equation 4(x-5)^2-21=-5 ?

The solutions to the equation 4(x-5)^2-21=-5 are x=7,x=3

Find the zeros of 4(x-5)^2-21=-5

The zeros of 4(x-5)^2-21=-5 are x=7,x=3

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4 (x - 5)^{2} - 21 = - 5

x = 7, x = 3

Solution steps

4 (x - 5)^{2} - 21 = - 5

Move

21

to the right side

4 (x - 5)^{2} = 16

Divide both sides by

4

(x - 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 4 : x = 7

Solve

x - 5 = - 4 : x = 3

The solutions to the quadratic equation are:

x = 7, x = 3

\frac{7}{\frac{1}{2}}

a^{2} - 8 a + 15 = 0

4 x = 4 x

- (6.24 c - 4.71) + 5.24 c = - 7.93

15 x - 13 < 77

What are the solutions to the equation 4(x-5)^2-21=-5 ?
The solutions to the equation 4(x-5)^2-21=-5 are x=7,x=3
Find the zeros of 4(x-5)^2-21=-5
The zeros of 4(x-5)^2-21=-5 are x=7,x=3