What is the answer to 14x-(3x-2)-[5x+2-(x-1)]=0 ?

The answer to 14x-(3x-2)-[5x+2-(x-1)]=0 is x= 1/7

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14x-(3x-2)-[5x+2-(x-1)]=0

14 x - (3 x - 2) - [5 x + 2 - (x - 1)] = 0

x = \frac{1}{7}

Decimal Notation

x = 0.14285 \dots

Solution steps

14 x - (3 x - 2) - [5 x + 2 - (x - 1)] = 0

Expand

14 x - (3 x - 2) - (5 x + 2 - (x - 1)) : 7 x - 1

7 x - 1 = 0

Move

1

to the right side

7 x = 1

Divide both sides by

7

x = \frac{1}{7}

3 (20) + 2 (18) \geq 93

y, x^{3} - x^{2} + 2 x y - y^{2} = 0

5 x - 15 > - 65

10 y + 4 - 7 y = - 17

- 2 (y + 1) + 5 y = 3 (y + 1) - 2

What is the answer to 14x-(3x-2)-[5x+2-(x-1)]=0 ?
The answer to 14x-(3x-2)-[5x+2-(x-1)]=0 is x= 1/7
Solve for x: 14x-(3x-2)-[5x+2-(x-1)]=0
The solution is x= 1/7