What are the solutions to the equation x^2+12x=-11 ?

The solutions to the equation x^2+12x=-11 are x=-1,x=-11

Find the zeros of x^2+12x=-11

The zeros of x^2+12x=-11 are x=-1,x=-11

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x^{2} + 12 x = - 11

x = - 1, x = - 11

Solution steps

x^{2} + 12 x = - 11

Move

11

to the left side

x^{2} + 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- 12 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 10}{2 \cdot 1}, x_{2} = \frac{- 12 - 10}{2 \cdot 1}

x = \frac{- 12 + 10}{2 \cdot 1} : - 1

x = \frac{- 12 - 10}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 1, x = - 11

e^{2}

lo g_{2} (8) + lo g_{2} (4)

3 (3 x - 1) \leq 7

75 a^{2} c - 45 a^{2} d - 30 b c + 18 b d

3 x^{2} + 7 x = - 2

What are the solutions to the equation x^2+12x=-11 ?
The solutions to the equation x^2+12x=-11 are x=-1,x=-11
Find the zeros of x^2+12x=-11
The zeros of x^2+12x=-11 are x=-1,x=-11