What are the solutions to the equation -y^2+17/4 y-1=0 ?

The solutions to the equation -y^2+17/4 y-1=0 are y= 1/4 ,y=4

Find the zeros of -y^2+17/4 y-1=0

The zeros of -y^2+17/4 y-1=0 are y= 1/4 ,y=4

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- y^{2} + \frac{17}{4} y - 1 = 0

y = \frac{1}{4}, y = 4

Decimal Notation

y = 0.25, y = 4

Solution steps

- y^{2} + \frac{17}{4} y - 1 = 0

Multiply both sides by

4

- 4 y^{2} + 17 y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 4 ) ( - 4 )}{2 ( - 4 )}

1 7^{2} - 4 (- 4) (- 4) = 15

y_{1, 2} = \frac{- 17 \pm 15}{2 ( - 4 )}

Separate the solutions

y_{1} = \frac{- 17 + 15}{2 ( - 4 )}, y_{2} = \frac{- 17 - 15}{2 ( - 4 )}

y = \frac{- 17 + 15}{2 ( - 4 )} : \frac{1}{4}

y = \frac{- 17 - 15}{2 ( - 4 )} : 4

The solutions to the quadratic equation are:

y = \frac{1}{4}, y = 4

8 x^{2} - 98 = 0

x - 3 (x - 6) \leq 4 x

3 x^{2} - 6 x + 7 = 0

- 2 x + 5 > 16

14 - x > 8

What are the solutions to the equation -y^2+17/4 y-1=0 ?
The solutions to the equation -y^2+17/4 y-1=0 are y= 1/4 ,y=4
Find the zeros of -y^2+17/4 y-1=0
The zeros of -y^2+17/4 y-1=0 are y= 1/4 ,y=4