What are the solutions to the equation x^2-1+x^2-16=2 ?

The solutions to the equation x^2-1+x^2-16=2 are x=sqrt(19/2),x=-sqrt(19/2)

Find the zeros of x^2-1+x^2-16=2

The zeros of x^2-1+x^2-16=2 are x=sqrt(19/2),x=-sqrt(19/2)

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x^{2} - 1 + x^{2} - 16 = 2

x = \frac{19}{2}, x = - \frac{19}{2}

Decimal Notation

x = 3.08220 \dots, x = - 3.08220 \dots

Solution steps

x^{2} - 1 + x^{2} - 16 = 2

Move

1

to the right side

x^{2} + x^{2} - 16 = 3

Move

16

to the right side

x^{2} + x^{2} = 19

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 19

Divide both sides by

2

x^{2} = \frac{19}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{19}{2}, x = - \frac{19}{2}

21 - 4

- 3 x^{2} + 6 x - 3 = 0

4 x - 22 = - 2

\frac{j}{3} > 3

x^{2} + 2 x + 4 > 0

What are the solutions to the equation x^2-1+x^2-16=2 ?
The solutions to the equation x^2-1+x^2-16=2 are x=sqrt(19/2),x=-sqrt(19/2)
Find the zeros of x^2-1+x^2-16=2
The zeros of x^2-1+x^2-16=2 are x=sqrt(19/2),x=-sqrt(19/2)