What are the solutions to the equation 8x^2+15x=7x-4 ?

The solutions to the equation 8x^2+15x=7x-4 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

Find the zeros of 8x^2+15x=7x-4

The zeros of 8x^2+15x=7x-4 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

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8 x^{2} + 15 x = 7 x - 4

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

Solution steps

8 x^{2} + 15 x = 7 x - 4

Move

4

to the left side

8 x^{2} + 15 x + 4 = 7 x

Move

7 x

to the left side

8 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

Simplify

8^{2} - 4 \cdot 8 \cdot 4 : 8 i

x_{1, 2} = \frac{- 8 \pm 8 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 8 + 8 i}{2 \cdot 8}, x_{2} = \frac{- 8 - 8 i}{2 \cdot 8}

x = \frac{- 8 + 8 i}{2 \cdot 8} : - \frac{1}{2} + i \frac{1}{2}

x = \frac{- 8 - 8 i}{2 \cdot 8} : - \frac{1}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

0.81

x^{2} + 3 x = 28

x^{2} + 18 x + 17

a^{2} \cdot a^{2}

3 y - 58 + y = 180

What are the solutions to the equation 8x^2+15x=7x-4 ?
The solutions to the equation 8x^2+15x=7x-4 are x=-1/2+i 1/2 ,x=-1/2-i 1/2
Find the zeros of 8x^2+15x=7x-4
The zeros of 8x^2+15x=7x-4 are x=-1/2+i 1/2 ,x=-1/2-i 1/2