What are the solutions to the equation -x^2+11x-5=0 ?

The solutions to the equation -x^2+11x-5=0 are x=(11-sqrt(101))/2 ,x=(11+sqrt(101))/2

Find the zeros of -x^2+11x-5=0

The zeros of -x^2+11x-5=0 are x=(11-sqrt(101))/2 ,x=(11+sqrt(101))/2

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- x^{2} + 11 x - 5 = 0

x = \frac{11 - 101}{2}, x = \frac{11 + 101}{2}

Solution steps

- x^{2} + 11 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

1 1^{2} - 4 (- 1) (- 5) = 101

x_{1, 2} = \frac{- 11 \pm 101}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 11 + 101}{2 ( - 1 )}, x_{2} = \frac{- 11 - 101}{2 ( - 1 )}

x = \frac{- 11 + 101}{2 ( - 1 )} : \frac{11 - 101}{2}

x = \frac{- 11 - 101}{2 ( - 1 )} : \frac{11 + 101}{2}

The solutions to the quadratic equation are:

x = \frac{11 - 101}{2}, x = \frac{11 + 101}{2}

4 > \frac{a}{20}

3 x^{3} - 54 y^{3} z^{3}

∣ x + 4 ∣ = 3 x - 5

4 n^{3} + n

x^{3} y - 8 + 8 y - x^{3}

What are the solutions to the equation -x^2+11x-5=0 ?
The solutions to the equation -x^2+11x-5=0 are x=(11-sqrt(101))/2 ,x=(11+sqrt(101))/2
Find the zeros of -x^2+11x-5=0
The zeros of -x^2+11x-5=0 are x=(11-sqrt(101))/2 ,x=(11+sqrt(101))/2