What are the solutions to the equation 25x^2+40x+17=0 ?

The solutions to the equation 25x^2+40x+17=0 are x=-4/5+i 1/5 ,x=-4/5-i 1/5

Find the zeros of 25x^2+40x+17=0

The zeros of 25x^2+40x+17=0 are x=-4/5+i 1/5 ,x=-4/5-i 1/5

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25 x^{2} + 40 x + 17 = 0

x = - \frac{4}{5} + i \frac{1}{5}, x = - \frac{4}{5} - i \frac{1}{5}

Solution steps

25 x^{2} + 40 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 25 \cdot 17}{2 \cdot 25}

Simplify

4 0^{2} - 4 \cdot 25 \cdot 17 : 10 i

x_{1, 2} = \frac{- 40 \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 40 + 10 i}{2 \cdot 25}, x_{2} = \frac{- 40 - 10 i}{2 \cdot 25}

x = \frac{- 40 + 10 i}{2 \cdot 25} : - \frac{4}{5} + i \frac{1}{5}

x = \frac{- 40 - 10 i}{2 \cdot 25} : - \frac{4}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = - \frac{4}{5} + i \frac{1}{5}, x = - \frac{4}{5} - i \frac{1}{5}

2 x^{3} - 3 x^{2} + x

\frac{2 x - 1}{x - 1} = 3

\frac{32 a ^{2} b c ^{3}}{20 ab c}

(2^{2})^{- 2}

(3 x - 4)^{2} = 8

What are the solutions to the equation 25x^2+40x+17=0 ?
The solutions to the equation 25x^2+40x+17=0 are x=-4/5+i 1/5 ,x=-4/5-i 1/5
Find the zeros of 25x^2+40x+17=0
The zeros of 25x^2+40x+17=0 are x=-4/5+i 1/5 ,x=-4/5-i 1/5