What are the solutions to the equation 2x^2+72=-12x ?

The solutions to the equation 2x^2+72=-12x are x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

Find the zeros of 2x^2+72=-12x

The zeros of 2x^2+72=-12x are x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

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2 x^{2} + 72 = - 12 x

x = - 3 + 33 i, x = - 3 - 33 i

Solution steps

2 x^{2} + 72 = - 12 x

Move

12 x

to the left side

2 x^{2} + 72 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 12 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 72}{2 \cdot 2}

Simplify

1 2^{2} - 4 \cdot 2 \cdot 72 : 123 i

x_{1, 2} = \frac{- 12 \pm 12 3 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 12 3 i}{2 \cdot 2}, x_{2} = \frac{- 12 - 12 3 i}{2 \cdot 2}

x = \frac{- 12 + 12 3 i}{2 \cdot 2} : - 3 + 33 i

x = \frac{- 12 - 12 3 i}{2 \cdot 2} : - 3 - 33 i

The solutions to the quadratic equation are:

x = - 3 + 33 i, x = - 3 - 33 i

12 - 7 t = 5 t - 4 (2 - 3 t)

5 (1 - n) + 3 n = 3 (n - 1) - 5 n

x - 2 = 7

x^{2} + 14 x = 14

What are the solutions to the equation 2x^2+72=-12x ?
The solutions to the equation 2x^2+72=-12x are x=-3+3sqrt(3)i,x=-3-3sqrt(3)i
Find the zeros of 2x^2+72=-12x
The zeros of 2x^2+72=-12x are x=-3+3sqrt(3)i,x=-3-3sqrt(3)i