What are the solutions to the equation x^2+14x=14 ?

The solutions to the equation x^2+14x=14 are x=-7+3sqrt(7),x=-7-3sqrt(7)

Find the zeros of x^2+14x=14

The zeros of x^2+14x=14 are x=-7+3sqrt(7),x=-7-3sqrt(7)

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x^{2} + 14 x = 14

x = - 7 + 37, x = - 7 - 37

Solution steps

x^{2} + 14 x = 14

Move

14

to the left side

x^{2} + 14 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 14) = 67

x_{1, 2} = \frac{- 14 \pm 6 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6 7}{2 \cdot 1}, x_{2} = \frac{- 14 - 6 7}{2 \cdot 1}

x = \frac{- 14 + 6 7}{2 \cdot 1} : - 7 + 37

x = \frac{- 14 - 6 7}{2 \cdot 1} : - 7 - 37

The solutions to the quadratic equation are:

x = - 7 + 37, x = - 7 - 37

5 b^{2} = 45 b

4 (2 a + b)^{2} + 4 (2 a + b) - 24

2 (\frac{48}{3})^{\frac{1}{4}}

x^{2} - 27 x + 176 = 0

\frac{m ^{2} - 9}{m - 3}

What are the solutions to the equation x^2+14x=14 ?
The solutions to the equation x^2+14x=14 are x=-7+3sqrt(7),x=-7-3sqrt(7)
Find the zeros of x^2+14x=14
The zeros of x^2+14x=14 are x=-7+3sqrt(7),x=-7-3sqrt(7)