What are the solutions to the equation 4x^2+8x+20=0 ?

The solutions to the equation 4x^2+8x+20=0 are x=-1+2i,x=-1-2i

Find the zeros of 4x^2+8x+20=0

The zeros of 4x^2+8x+20=0 are x=-1+2i,x=-1-2i

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4 x^{2} + 8 x + 20 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

4 x^{2} + 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 20 : 16 i

x_{1, 2} = \frac{- 8 \pm 16 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 16 i}{2 \cdot 4}, x_{2} = \frac{- 8 - 16 i}{2 \cdot 4}

x = \frac{- 8 + 16 i}{2 \cdot 4} : - 1 + 2 i

x = \frac{- 8 - 16 i}{2 \cdot 4} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

2 x^{4} - 7 x^{3} + 3 x^{2} + 8 x - 4

3 X^{2} = - 99

(9 x)^{2}

4 a^{2} - 25

c^{2} - 16

What are the solutions to the equation 4x^2+8x+20=0 ?
The solutions to the equation 4x^2+8x+20=0 are x=-1+2i,x=-1-2i
Find the zeros of 4x^2+8x+20=0
The zeros of 4x^2+8x+20=0 are x=-1+2i,x=-1-2i