What are the solutions to the equation x^2+14x+47=0 ?

The solutions to the equation x^2+14x+47=0 are x=-7+sqrt(2),x=-7-sqrt(2)

Find the zeros of x^2+14x+47=0

The zeros of x^2+14x+47=0 are x=-7+sqrt(2),x=-7-sqrt(2)

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x^{2} + 14 x + 47 = 0

x = - 7 + 2, x = - 7 - 2

Decimal Notation

x = - 5.58578 \dots, x = - 8.41421 \dots

Solution steps

x^{2} + 14 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 47}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 47 = 22

x_{1, 2} = \frac{- 14 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 2}{2 \cdot 1}

x = \frac{- 14 + 2 2}{2 \cdot 1} : - 7 + 2

x = \frac{- 14 - 2 2}{2 \cdot 1} : - 7 - 2

The solutions to the quadratic equation are:

x = - 7 + 2, x = - 7 - 2

4 x^{2} - x + 3 = 0

9 k^{2} - 30 k + 25

3 (x + 5) = 2 (- 6 - x) - 2 x

\frac{n ( n + 1 )}{2} + n + 1

- \frac{24}{- 6}

What are the solutions to the equation x^2+14x+47=0 ?
The solutions to the equation x^2+14x+47=0 are x=-7+sqrt(2),x=-7-sqrt(2)
Find the zeros of x^2+14x+47=0
The zeros of x^2+14x+47=0 are x=-7+sqrt(2),x=-7-sqrt(2)